Verify
(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)=0
Answers
Answered by
2
Step-by-step explanation:
if it's answer is 0 then use this
0+0 =0
0x0= 0
so all charrecters are 0
Answered by
6
Answer:
(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)=0
(a^2 - b^2) + (b^2 - c^2) + (c^2 - a^2) = 0
a^2 - b^2 + b^2 - c^2 + c^2 - a^2 = 0
a^2 - a^2 - b^2 + b^2 - c^2 + c^2 = 0
0 - 0 - 0 = 0
0 = 0
hence proved L.H.S = R.H.S
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