verify (a+b+c)^2=a^2+b^2+c^2+ab+bc+ca i want a quick answer plzzzz
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(a+b+c)²
=(a+b+c) × (a+b+c)
=[a×(a+b+c)] + [b×(a+b+c)] +[c×(a+b+c)] (by distributive law)
= [a² + ab + ac] + [ ba +b² + bc] + [ ca + cb + c²]
= a² + ab + ac + ba +b² + bc + ca + cb + c²
= a² + ab + ac + ab +b² + bc + ac + bc + c² (ab=ba)
= a² + b² + c² + ab + ab + bc + bc + ac + ac
= a² + b² + c² + 2ab + 2bc + 2ca
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