Question

verify (a+b+c)^2=a^2+b^2+c^2+ab+bc+ca i want a quick answer plzzzz

Answer 1

Answer:

(a+b+c)²

=(a+b+c) × (a+b+c)

=[a×(a+b+c)] + [b×(a+b+c)] +[c×(a+b+c)] (by distributive law)

= [a² + ab + ac] + [ ba +b² + bc] + [ ca + cb + c²] 

= a² + ab + ac + ba +b² + bc + ca + cb + c²

= a² + ab + ac + ab +b² + bc + ac + bc + c²   (ab=ba)

= a² + b² + c² + ab + ab + bc + bc + ac + ac

= a² + b² + c² + 2ab + 2bc + 2ca

Answer 2

Answer:

Step-by-step explanation:

See the screenshot below