verify a ×(b+c)=(a×b)+(a×c) when a = 42,b=7 and c=( -3)
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Answer:
a×(b+c)=(a×b)+(a×c)
42×(7+(-3))=(42×7)+(42×-3)
42×4= 294+(-126)
168= 168
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Step-by-step explanation:
- a×(b+c)=(a×b)+(a×c)
- 42(7+(-3))=(42×7)+(42×(-3))
- 42(4)=(294)+(-126)
- 168=(294-126)
- 168=168
- hence,verified
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