verify a×(b×c)=(a×b)×c by taking a=_4/7 b,14/15 and c,_3/4a
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Answer:
Taking LHS.
a=4/7
a=4/7b= 14/15
a=4/7b= 14/15c=3/4a
a=4/7b= 14/15c=3/4a =3/(4x4/7)
a=4/7b= 14/15c=3/4a =3/(4x4/7) = (3x7)/4x4
a=4/7b= 14/15c=3/4a =3/(4x4/7) = (3x7)/4x4 =21/16
a=4/7b= 14/15c=3/4a =3/(4x4/7) = (3x7)/4x4 =21/16 ax(bxc)
a=4/7b= 14/15c=3/4a =3/(4x4/7) = (3x7)/4x4 =21/16 ax(bxc) =4/7x(14/15x21/16)
a=4/7b= 14/15c=3/4a =3/(4x4/7) = (3x7)/4x4 =21/16 ax(bxc) =4/7x(14/15x21/16)=7/10
Taking RHS
(axb)xc
(axb)xc=(4/7x14/15)x21/16
(axb)xc=(4/7x14/15)x21/16=7/10
RHS=LHS
THUS VERIFIED
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