Question

verify (a+b)+c= a+(b+c) when a = -9/11 , b= 3/5 ,c = -9/22​

Answer 1

☑️ Given that :

• a = -9/11
• b = 3/5
• c = -9/22

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☑️ To Verify :

$\implies$(a + b) + c = a + (b + c)

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$\huge{\{\blue{\boxed{\boxed{\sf{\underline{\underline{\orange{.SoLutiOn.}}}}}}}}$

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On Taking L.H.S.

$\implies$ (a + b) + c

$= (- \frac{9}{11} + \frac{3}{5}) + ( - \frac{9}{22})$

$= \frac{ - 45 + 33}{55} - \frac{9}{22}$

$= \frac{ - 12 }{55} - \frac{9}{22}$

$= \frac{ - 24 - 45 }{110}$

$= - \frac{ 69 }{110}$

Now, taking R.H.S.

$\implies$ a + (b + c)

$= - \frac{9}{11} + (\frac{3}{5} - \frac{9}{22})$

$= - \frac{9}{11} + \frac{66 - 45}{110}$

$= - \frac{9}{11} + \frac{21}{110}$

$= \frac{ - 90 + 21}{110}$

$= - \frac{ 69 }{110}$

$\therefore$ $\large{\boxed{\sf{\underline{\green{L.H.S. = R.H.S.}}}}}$

Hence, Verified.

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⋰ Hope It Will Be Helpful To You Mate ⋱

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