Verify a×( b+ c ) = axb + bxc if a = 7/15, b = 1/7, c = 3/14
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Answer:
a×(b+c)= (a×b) + ( a×c) = 1/6
Step-by-step explanation:
LHS = a × (b+c) = 7/15 × ( 1/7 + 3/14)
= 7/15 × ( 2/7 + 3/14)
= 7/15 × 5/14
= 1/ 6
now
RHS = ( a×b) + ( a×c) =( 7/15 × 1/7) + ( 7/15×3/14)
= (1/15)+(1/10)
= (10+15) / 150
= 25/150
= 1/6
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