verify A×(BnC)=(AnB)×(AnC)
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Answer:
let's take A=1,2. B=2,3.c=1,3.
step 1
A×(BnC)
BnC={2,3}n {1,3}
={3}
A×(BnC)= {1,2}×{3}
{1,2}
step 2
AnB ={1,2}n{2,3}
={2}
AnC={1,2}n{1,3}
={1}
(AnB)×(AnC)={2}× {1}
={2,1}
now, step1 and step 2 is same
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