Question

verify a²b²c²=(ab)*(bc)*(ca), for a=3 and b =4.​

Answer 1

Answer:

${a}^{2} {b}^{2} {c}^{2} = (ab)(bc)(ca) \: \: \: (given) \\ \\ for \: a = 3 \: and \: b = 4 \\ \\lhs - \\ {(3)}^{2} + {(4)}^{2} + {c}^{2} \\ = > 9 \times 16 \times {c}^{2} \\ = > 144 {c}^{2} \\ \\ rhs - \\ (3 \times 4)(4 \times c)(c \times 3) \\ = > (12)(4c)(3c) \\ = > (12)(12 {c}^{2} ) \\ = > 144 {c}^{2}$

$since \: 144 {c}^{2} = 144 {c}^{2} \\ therefore \: lhs = rhs$

Hence,Verified