Verify a²b²c²=(ab)×(bc)×(ca),for a=3andb=4
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Answered by
5
Answer:
a²b²c²=(ab)×(bc)×(ca),for
Answered by
6
Answer:
Consider, a
2
+b
2
+c
2
–ab–bc–ca=0
Multiply both sides with 2, we get
2(a
2
+b
2
+c
2
–ab–bc–ca)=0
⇒ 2a
2
+2b
2
+2c
2
–2ab–2bc–2ca=0
⇒ (a
2
–2ab+b
2
)+(b
2
–2bc+c
2
)+(c
2
–2ca+a
2
)=0
⇒ (a–b)
2
+(b–c)
2
+(c–a)
2
=0
Since the sum of square is zero then each term should be zero
⇒ (a–b)
2
=0,(b–c)
2
=0,(c–a)
2
=0
⇒ (a–b)=0,(b–c)=0,(c–a)=0
⇒ a=b,b=c,c=a
∴ a=b=c.
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