Question

verify (ab+ bc) (ab-bc) + (bc+ca) (bc-ca)+ (ca+ab) (ca-ab) =0

Answer 1

LHS = (ab+ bc) (ab-bc) + (bc+ca) (bc-ca)+ (ca+ab) (ca-ab)

= (ab)² - (bc)² + (bc)² - (ca)² + (ca)² - (ab)²

______________

/* By Algebraic Identity */

( x + y )( x - y ) = x² - y²

_____________

= 0

= RHS

•••♪

Answer 2

Step-by-step explanation:

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