Question

verify: ax(bxC) = (axb) ×C for a=11 ; b=7 ; C=-2

I want this answer by full and full explanation
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Answer 1

$\large\bold{\underline{\underline{Given:-}}}$

$a = 11$

$b = 7$

$c = - 2$

$\large\bold{\underline{\underline{To\:verify:-}}}$

$a \times (b \times c) = (a \times b) \times c$

$\large\bold{\underline{\underline{Solution:-}}}$

Let us first solve for L. H S.

:⟼  $a \times (b \times c)$

:⟼  $11 \times (7 \times - 2)$

:⟼  $11 \times ( - 14)$

:⟼  $\boxed{ -154 }$

Next, we have R. H. S.

:⟼  $(a \times b) \times c$

:⟼  $(11 \times 7) \times ( - 2)$

:⟼  $77 \times ( - 2)$

:⟼  $\boxed{ -154 }$

Since L. H. S. = R. H. S.

$\bigstar \: \boxed{\sf{\color{red}{Hence\:verified! }}}$

Answer 2

Answer: True

Hiiii, I really hope my answer helps you a lot!!

Step-by-step explanation:

So, to verify we have to find the values of ax(bxC) and (axb) × C

Given the values;

a = 11

b = 7

c = -2

We just need to substitute; and solve

ax(bxC) =

$11x (7x \times - 2)$

$11x( - 14x)$

* Remember brackets should be solve first

$= - 154x$

(axb) × C =

$(11x \times 7) \times - 2$

This is the same as -2(11x × 7)

$- 2( 77x)$

$= - 154x$