Verify ax(bxc)=(axb)xc for a=6/7 , b= -9/4 and c= 1/2 please answer in long
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Step-by-step explanation:
Given:-
- a= 6/7
- b= -9/4
- c= 1/2
To verify:-
- a×(b×c)= (a×b)×c
LHS :-
=> a×(b×c)
=> 6/7×(-9/4×1/2)
=> 6/7×(-9/8)
=> 6/7×-9/8
=> -54/56
=> -38/28
=> -19/14
RHS :-
=> (a×b)×c
=> (6/7×-9/4)×1/2
=> (-54/28)×1/2
=> -54/28×1/2
=> -54/56
=> -38/28
=> -19/14
Therefore
LHS=RHS, Hence verified
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