Question

Verify by calculating that :

5 moles of CO2 has higher mass than 5 moles of H2O

120 g of calcium and 120 g of magnesium elements have a mole ratio of 3:5

plz answer fast

Answer 1

solution to the asked query:1) a)  Molar mass of CO2 = 44 gMolar mass of H2O = 18 g Mass of 1 mole of CO2 = 44 gHence, mass of 5 moles of CO2 = 5×44 = 220 g b) Massof 1 mole of H2O = 18 gMass of 5 moles of H2O= 5×18 = 90 g Hence , mass of 5 moles of CO2 is higher than mass of 5 moles of H2O . 2) Molar mass of calcium = 40 gGiven mass of calcium =120 gNumber of moles (n) = Given massMolar massn = 12040= 3 moles Molar mass of magnesium = 24 gGiven mass of magnesium = 120 gn = 12024 = 5 molesHence , the mole ratio will be 3 : 5 . To practice with some more questions following are the links of the similar queries as asked by you:

Answer 2

Chemical Reactions(Verification)

We have,

(1) 5 moles of CO2 and 5 moles of H2O
Have to prove that mass of 5 moles of CO2 > mass of 5 moles of H2O

And,
(2)120 gm of Ca and 120 gm of Mg.
Have to prove that the ratio of moles is 3:5

(1) Mass of 1 mole of CO2 (12 + 2×16) gm
= 44 gm
And mass of 1 mole of H2O (2×1 + 16) gm
= 18 gm

So five moles of CO2 will have mass = 5×44 = 220 gm
And five moles of H2O will have mass = 5 × 18 = 90 gm.

Clearly 220 > 90
So, mass of 5 moles of CO2 > mass of 5 moles of H2O [proved]

(2) 1 mole fo Ca weights 40 gm
So 120 gm of Ca will have 120/40 = 3 moles of Ca.

And,1 mole of Mg weights 24 gm
So 120 gm of Mg will have 120/24 = 5 moles of Ca.

Now the ratio of moles of Ca and Mg is 3:5 [proved]