Question

verify by calculating the following: (a) number of molecules in 100g of NH3 is more than 100g of N2 ( atomic number of N =14u, H=1u)

Answer 1

M,Molar mass of NH₃=14+(1×3)=17
m,Given mass=100 g
n,number of moles=m/M=100/17
n=N/N₀
N=n×N₀=(100/17)×6.022×10²³
=3.55×10²⁴

M,Molar mass of N₂=14×2=28
m,Given mass=100 g
n,number of moles=m/M=100/28
n=N/N₀
N=n×N₀
(100/28)×6.022×10²³=2.15×10²⁴

∴Number of molecules in 100 g of NH3 is more than 100 g of N2.

Answer 2

Answer:

Answer: 100 gram of NH3 has more atoms than 100 g of N2

Explanation:

Number of molecules of NH3 = number of moles x Avogadro number. Since, NH3 is tetratomic molecule which contain one atoms of nitrogen and three atom of hydrogen.

No. of moles = Weight of the substance/Molecular weight of the substance

N2

100 gms of N2 = (100/2) x 14 moles

100 gms of N2 = 100/28 moles

Number of molecules = (100/28) x 6.022 x 10²³

Molar mass of N2 = 2 x molar mass of monoatomic N

Molar mass of N2 = 2 x 14.0067

Molar mass of N2 = 28 moles.

Number of molecules = (100/28) x 6.022 x 10²³

Number of atoms = 2 x (100/28) x 6.022 x 10²³

Number of atoms = 43.01 x 10²³

NH3

100 gm of NH3 = 100/17 moles

Number of molecules = (100/17) x 6.022 x 10²³ molecules

Number of atoms in NH3 = 4 x (100/17) x 6.022 x 10²³

Number of atoms in NH3 = 141.69 x 10²³ atoms.

Therefore, NH3 has more atoms than N2.

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