Math, asked by pontingchatterjee111, 3 months ago

Verify by the method of contradiction that √3 is irrational​

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Answered by panwarsanjay112
1

Answer:

हिंदी में खोजें

हिंदी में खोजेंविरोधाभास है कि की विधि द्वारा की पुष्टि √3 तर्कहीन है

हिंदी में खोजेंविरोधाभास है कि की विधि द्वारा की पुष्टि √3 तर्कहीन हैSince both q and r are odd, we can write q=2m−1 and r=2n−1 for some m,n∈N. We note that the lefthand side of this equation is even, while the righthand side of this equation is odd, which is a contradiction. Therefore there exists no rational number r such that r2=3. Hence the root of 3 is an irrational number.

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