Question

Verify by the method of contradiction that square root of 7 is irrational
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Answer 1

Step-by-step explanation:

let us assume that √7 is rational.

therefore,

√7 = a/b

squaring on both sides,

7 = a^2 / b^2

as 7 is a factor of a^2 therefore, 7 is a factor of a .

a = 7c

squaring on both side

a^2 = 5^2c^2

5b^2 = 5^2c^2

b^2 = 5c^2

as 7 is a factor of b^2 therefore, 7 is a factor of b .

thus 7 is not a factor of a and b

as, a abd b are not co-prime

therefore, √7 is irrational

hope it helps....