Question

Verify commutative property of the addition for the following pair of numbers.

1. -4/3 and 3/7
2. -2/-5 and 1/3
3. 9/11 and 2/13

Answer 1

☑️ Given pairs of Numbers :

$1). \: - \frac{4}{3} \: and \: \frac{3}{7}$

$2). \: \frac{ - 2}{ - 5} \: and \: \frac{1}{3} = \frac{2}{5} \: and \: \frac{1}{3}$

$3). \: \frac{9}{11} \: and \: \frac{2}{13}$

━━━━━━━━━━━━━━━━━━━━━━━━

☑️ To Verify :

Commutative Property of Addition.

━━━━━━━━━━━━━━━━━━━━━━━━

$\large{\sf{\underline{\underline{\pink{\bigstar{Commutative \: Property \: Of \: Addition }}}}}}$

A + B = B + A

Where A and B are the real numbers.

━━━━━━━━━━━━━━━━━━━━━━━━

$\huge{\{\yellow{\boxed{\boxed{\mathfrak{\underline{\underline{\maroon{\bigstar{.SoLutiOn.}}}}}}}}}$

━━━━━━━━━━━━━━━━━━━━━━━━

$1). \: A + B = - \frac{4}{3} + \frac{3}{7}$

$\implies\: A + B = \frac{ - 28 + 9}{21}$

$\implies\: A + B = \frac{ - 19}{21}$

Also,

$B + A = \frac{3}{7} + ( - \frac{4}{3} )$

$\implies\: B + A = \frac{3}{7} - \frac{4}{3}$

$\implies\: B + A = \frac{9 - 28}{21}$

$\implies\: B + A = \frac{ - 19}{21}$

$\therefore$ A + B = B + A

Hence, verified.

━━━━━━━━━━━━━━━━━━━━━━━━

$2). \: A + B = \frac{2}{5} + \frac{1}{3}$

$\implies \: A + B = \frac{6 + 5}{15}$

$\implies \: A + B = \frac{11}{15}$

Also,

$B + A = \frac{1}{3} + \frac{2}{5}$

$\implies \: B + A = \frac{5 + 6}{15}$

$\implies \: B + A = \frac{11}{15}$

$\therefore$ A + B = B + A

Hence, Verified.

━━━━━━━━━━━━━━━━━━━━━━━━

$3). \: A + B = \frac{9}{11} + \frac{2}{13}$

$\implies \: A + B = \frac{117 + 22}{143}$

$\implies \: A + B = \frac{139}{143}$

Also,

$B + A = \frac{2}{13} + \frac{9}{11}$

$\implies \: B + A = \frac{22 + 117}{143}$

$\implies \: B + A = \frac{ 139}{143}$

$\therefore$ A + B = B + A

Hence, Verified.

━━━━━━━━━━━━━━━━━━━━━━━━

⋰ Hope It Will Be Helpful To You Mate ⋱

#be_brainly