Verify equation v=u+at in dimensional analysis
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Dimensional formula of v is [M^0LT^-1]
Dimensional formula of u is [M^0LT^-1]
Dimensional formula of a is [M^0LT-2]
Dimensional formula of t is [M^0L^0T]
L. H. S is the dimensional formula of v=[M^0LT-1]
R. H. S is the dimensional formula of u+dimensional formula of a × dimensional formula of t.
=[M^0LT-1]+[M^0LT^-2]×[M^0L^0T]
=[M^0LT^-1]+[M^0LT^-1]
=2[M^0LT^-1]
Since 2 is a dimensionless constant, therefore L. H. S = R.H.S
Hence the given equation is dimensionally correct.
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