verify experimentally that the median of an isosceles triangle is perpendicular to the base.
Answers
Answered by
0
Answer:
median divides the base of an isosceles triangle into two equal halves.
so let the angles be x(angles are equal as median divides the base of an isosceles triangle into two equal halves)
therefore,x+x=180(angles on a straight line and the line is the median)
2x=180
x=90
so the median of an isosceles triangle is perpendicular to the base.
Answered by
0
Answer:
Let ABC is an isosceles triangle with AB=AC and let AD be the median to the base BC. Then D is the mid-point of BC.
ΔABD≅ΔADC by SSS
So, ∠ADC =∠ADB=x °
∴ ∠ADB+∠ADC=180°
x+x=180 °
2x = 180 °
x = 90°
∴ ∠ADB=∠ADC= 90°
Hope this is helpful....
Similar questions