verify for any rational numbers x, y and z. (x+y)+z=x+(y+z) name the property
Answers
Answered by
0
Answer:
So, x×(y+z)=(x×y)×z
Step-by-step explanation:
(a) x×(y×z)
=1×(
2
−1
×
4
1
)
=1×(
8
−1
)
=
8
−1
(x×y)×z
=(1×
2
−1
)×
4
1
=
2
−1
×
4
1
=
8
−1
So x×(y×z)=(x×y)z
(b)x×(y×z)=
3
2
×(
7
−3
×
2
1
)
=
3
2
×
14
−3
=
42
−6
(x×y)×z=(
3
2
×
7
−3
)
=
21
−6
×
2
1
=
42
−6
=
2
−6
So, x×(y+z)=(x×y)×z
Answered by
0
Answer:
In the question is given to verify the property x × (y × z) = (x × y) × z
The arrangement of the given rational number is as per the rule of associative property for multiplication.
Then,
(-2/7) × (-5/6 × ¼)
= ((-2/7) × (-5/6)) × ¼ LHS
= (-2/7) × (-5/6 × ¼)
= (-2/7) × (-5/24)
= 10/168 RHS
= ((-2/7) × (-5/6)) × ¼
= (10/42) × ¼
= 10/168
By comparing LHS and RHS LHS = RHS
∴ 10/168 = 10/168
Hence x × (y × z) = (x × y) × z
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