Verify geometrically, that the polynomial
p(x) = x2 + 6x + 9 has only one real zero.
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Step-by-step explanation:
x2+6x+9
=x2+6x+9
=x2+3x+3x+9
=x(x+3)+3(x+3)
=(x+3)(x+3)
hence
x= -3 ,-3
so x2+6x+9 has only one real zero
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