Verify: (i)( x³+ y³) = (x + y)(x²- xy + y²)
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Hey mate
Here's ur answer
(i) x³+ y³ =(x + y)(x² –xy+y²)
We know that,
(x +y)³ = x³ + y³ + 3xy(x + y)
⇒ x³ + y³ = (x + y)³ – 3xy(x + y)
⇒ x³ + y³ = (x + y)[(x + y)² – 3xy]
[Taking (x+y) Common]
⇒ x³+ y³= (x + y)[(x²+ y² + 2xy) – 3xy]
⇒ x³+ y³ = (x + y)(x² + y² – xy)
L.H.S= R.H.S
razzkumar96:
thanks
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