Question

Verify m²-
$\sqrt{2 \: \: m + 2}$
polynomial
omial or not
give
reason ?​

Answer 1

Solution = 1 - cubic polynomial with variable "x"

1 - cubic polynomial with variable "x"2- it is not a polynomial because in polynomial there can not be algebraic expression in denominator.

1 - cubic polynomial with variable "x"2- it is not a polynomial because in polynomial there can not be algebraic expression in denominator.3- it is a quadratic polynomial having " z" as variable.

1 - cubic polynomial with variable "x"2- it is not a polynomial because in polynomial there can not be algebraic expression in denominator.3- it is a quadratic polynomial having " z" as variable.4- it is also a quadratic polynomial with variable "m ".

1 - cubic polynomial with variable "x"2- it is not a polynomial because in polynomial there can not be algebraic expression in denominator.3- it is a quadratic polynomial having " z" as variable.4- it is also a quadratic polynomial with variable "m ".5- it is not polynomial because polynomial can not have negative exponent .

1 - cubic polynomial with variable "x"2- it is not a polynomial because in polynomial there can not be algebraic expression in denominator.3- it is a quadratic polynomial having " z" as variable.4- it is also a quadratic polynomial with variable "m ".5- it is not polynomial because polynomial can not have negative exponent .hence, expression (1), (3),(4) are polynomial, and expression (2) and (5) are not polynomials'

1 - cubic polynomial with variable "x"2- it is not a polynomial because in polynomial there can not be algebraic expression in denominator.3- it is a quadratic polynomial having " z" as variable.4- it is also a quadratic polynomial with variable "m ".5- it is not polynomial because polynomial can not have negative exponent .hence, expression (1), (3),(4) are polynomial, and expression (2) and (5) are not polynomials'algebraic expressions.

1 - cubic polynomial with variable "x"2- it is not a polynomial because in polynomial there can not be algebraic expression in denominator.3- it is a quadratic polynomial having " z" as variable.4- it is also a quadratic polynomial with variable "m ".5- it is not polynomial because polynomial can not have negative exponent .hence, expression (1), (3),(4) are polynomial, and expression (2) and (5) are not polynomials'algebraic expressions."thanks for this question"

1 - cubic polynomial with variable "x"2- it is not a polynomial because in polynomial there can not be algebraic expression in denominator.3- it is a quadratic polynomial having " z" as variable.4- it is also a quadratic polynomial with variable "m ".5- it is not polynomial because polynomial can not have negative exponent .hence, expression (1), (3),(4) are polynomial, and expression (2) and (5) are not polynomials'algebraic expressions."thanks for this question"【 hope it helps 】

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Answer 2

YES , THIS IS A POLYNOMIAL

CAUSE - BECAUSE THE POWER OF THE VARIABLES IS IN WHOLE NUMBER.

$\huge \underline{ \tt \red{hope \: this \: helps}}$