Question

verify minus one upon root 2 is the Zero of p (x) is equals to 2 x square - 1​

Answer 1

Answer:

$- \frac{1}{ \sqrt{2} } is \: the \: zero \: of \: p(x) </p><p>\\ \\ p(x) = 2 {x}^{2} - 1</p><p> \\ \\ put \: \: x = - \frac{1}{ \sqrt{2} } </p><p> \\ \\ 2( - \frac{1}{ \sqrt{2} }}^{2} - 1 </p><p>\\ \\ 2 \times \frac{1}{2} - 1 </p><p>\\ \\ = > 1 - 1 = 0</p><p> \\ \\ it \: shows \: that \: \frac{ - 1}{ {2}^{2} } \: is \: the \: of \: \: p(x)$

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