Question

Verify quadratic equation, x³-4x³-x+1=(x-2)³

Answer 1

Step-by-step explanation:

=(x-2)^3

=identity=(a-b)^3=a^3-b^3-3ab(a-b)

=(x)^3-(2)^3-3(x)(-2)[x-2]

=x^3-8+6x[x-2]

=x^3-8+6x^2-12x

=x^3+6x^2-12x-8

Answer 2

x³-4x²-x+1=(x-2)³

x³-4x²-x+1=(x)³-(2)³-3×x×2(x-2)

x³-4x²-x+1=x³-8-6x(x-2)

x³-4x²-x+1=x³-8-6x²+12x

x³-x³-4x²+6x²-x-12x= -8-1

2x²-13x= -9

2x-13x=√-9

15x =-3

x= -3/15

x= -1/5

minus×minus=plus

minus×plus=minus

I hope it help you