verify relationship between 4xsquare-9
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Answer:
Let p(x)=4x^2-9
To find zeroes make p(x)=0
4x^2-9=0
(2x)^2-3^2=0
(2x+3)(2x-3)=0
Therefore
2x+3=0 or 2x-3=0
2x=-3 or 2x=3
x=-3/2 or x=3/2
Two zeroes are p=-3/2, q=3/2
ii) compare given equation with ax^2+bx+c=0
a=4, b=0,c=-9
Sum of the zeroes = -b/a
p+q= -0/4=0
p+q=-3/2+3/2=0
iii)product of the zeroes =c/a
pq=-9/4
(-3/2)(3/2)=-9/4
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