verify relationships between zero and coefficients
×^2-7^×-8
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Step-by-step explanation:
First solve the quadratic equation and then by roots and coefficient verify the relationshios
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x^2-7x-8
The relationship between the zero alpha and beta in a quadratic polynomial with the coefficient is:
alpha + beta = -b/a (b = Coefficient of x,a = coefficient of x^2)(1)
apha * beta = c/a (c = constant,a = coefficient of x^2)(2)
Now let's find the zeroes with factorization method.
=>X^2-7x-8
x^2-8x+1x-8
x(x-8) + 1(x-8)
(x+1)(x-8)
Therefore the zeroes are -1 and 8 respectively:
Now from (1)
-1 + 8 = -(-7)/1
7 = 7
Now from (2)
-1 * 8 = -8/1
-8 = -8
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