Question

Verify Rolle’s Theorem for f(x) =

3

in the interval (-1,1)​

Answer 1

Answer:

Idk

Step-by-step explanation:

Idk

Answer 2

Answer:

Rolle's Theorem : (i)f(a)=f(b)

(ii)f(x) is continous in [ab]

(iii)f(x) is differential in (a,b)

So, f(x)=0(0−1)

2

=0

f(1)=1(1−2)

2

=0

f(0)=f(1).

So , f(x)=x(x−1)

2

is satisfy Rolle's theorem.

Step-by-step explanation:

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