Question

verify sin^2 60°+cos^2 60° = 1​

Answer 1

${\large{\text{\underline{\underline{\red{Solution :}}}}}}$

$\implies \sin^260°+\cos^260°=1$

$\sin 60 °=\frac{\sqrt{3}}{2}\:;\:\cos60°=\frac{1}{2}$

$\text{LHS} = \sin^260°+cos^2°$

$\implies (\frac{\sqrt{3}}{2})^2+(\frac{1}{2})^2$

$\implies \frac{3}{4} +\frac{1}{4}$

$\implies \frac{4}{4} = 1$

$\text{L.H.S = R.H.S}$

$\text{Hence it is proved}$