Question

verify sin square theta + cos square theta is equal to 1 for theta is equal to zero degrees, 30° 45° 60° 90°​

Answer 1

Let ABC be a right angled triangle right angled at B.

Let angle C ie angle ACB = theeta.

Now by Pythagoras theorem

AC^2= AB^2+BC^2 ……(1)

We know that sin theeta = opposite side/ hypotenuse.

So sin theeta = AB/AC. Similarly

cos theeta= adjacent side/ hypotenuse

So cos theeta = BC/AC

Now sin^2 theeta + cos^2 theeta

= (AB/AC)^2 + (BC/AC)^2

= AB^2/AC^2 + BC^2/AC^2

= (AB^2+BC^2)/AC^2

Answer 2

Answer:

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