Question

Verify :

$1)( - {2})^{4} \times ( - {2})^{3} = ( - {2})^{7}$
$2) \: {3}^{7} \div {3}^{2} = {3}^{5}$
Ch = EXPONENTS AND POWERS....​

Answer 1

✪ GIVEN :

$1)( - {2})^{4} \times ( - {2})^{3} = ( - {2})^{7}$

We know that if multiplication happens in two same numbers there power should be added.

Same like that when division happens in two same numbers there power should be subtracted.

so,

( -2)4×(-2)3= (-2)7

✪ VERIFIED :

LHS = RHS

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Answer 2

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ANSWER :

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✪ GIVEN :

$\sf{ \implies\: \: ( - {2})^{4} \times ( - {2})^{3} = ( - {2})^{7}}$

✪ SOLUTION :

• We need to know that if multiplication happens in two numbers there power should be added.

so,

$\implies\sf{{( - 2)}^{4 + 3} =({-2})^{7}}$

$\implies\sf{{( - 2)}^{7} = {(-2)}^{7}}$

✪ VERIFIED :

• LHR = RHS

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✪ GIVEN :

$\implies \sf{{(3)}^{7}\div (3)^{2} = {(3)}^{5}}$

• We know that if multiplication happens in two numbers there power should be added.

• same like that when division happens in two numbers there power should be subtracted.

so,

$\implies \sf{{(3)}^{7 - 2} = {(3)}^{5} }$

$\implies\sf{{(3)}^{5} ={(3)}^{5}}$

✪ VERIFIED :

• LHS = RHS

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