Question

verify
$\frac{ -4}{3} ( \frac{6}{ - 5} \times \frac{8}{9} ) = ( \frac{ - 4}{3} \times \frac{6}{ - 5} ) \times \frac{8}{9}$
pls Help Me

Answer 1

Hey friend,
Here is the answer you were looking for:
$\frac{ - 4}{3} ( \frac{6}{ - 5} \times \frac{8}{9} ) = ( \frac{ - 4}{3} \times \frac{6}{ - 5} ) \times \frac{8}{9} \\ \\ = \frac{ - 4}{3} ( \frac{2}{ - 5} \times \frac{8}{3} )=( \frac{ - 4}{1} \times \frac{2}{ - 5}) \times \frac{8}{9} \\ \\ \frac{ - 4}{3} ( \frac{16}{ - 15} ) = ( \frac{ - 8}{ - 5} ) \frac{8}{9} \\ \\ \frac{ - 4}{3} \times \frac{16}{ - 15} = \frac{8}{5} \times \frac{8}{9} \\ \\ \frac{ - 64}{ - 45} = \frac{64}{45} \\ \\ \frac{64}{45} = \frac{64}{45}$


Hence verified...


Hope this helps!!!

@Mahak24

Thanks...
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