Verify that 0 and 3 are the zeros of Polynomial p(x) = x² - 3x ??
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Step-by-step explanation:
p(x)=x^2-3x
p(0)=0^2-3×0
p(0)=0-0
p(0)=0
p(x)=x^2-3x
p(3)=3^2-3×3
p(3)=9-9
p(3)=0
Hence proved
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