Question

Verify that 0 and -4 are the zeros of a polynomial px=x2 + 4x

Answer 1

$</p><p></p><p>\underline{\underline{{\color{cyan}Given\: Question\;Is }}} \\\\</p><p></p><p>{\color{red}p(x)=x^2+4x} \\\\</p><p></p><p>{\underline{\underline{\color{cyan} Answer}}} \\\\</p><p></p><p></p><p>{\color{green}p(x)=x^2+4x} \\\\</p><p></p><p></p><p>{\color{green}For\:x=0\;we\; have} \\\\</p><p></p><p></p><p>{\color{green}p(0)=(0)^2+4(0)} \\\\</p><p></p><p></p><p>{\color{green}p(0)=0} \\\\</p><p></p><p>{\color{green}0=0} \\\\</p><p></p><p></p><p>\therefore\;\;{\color{cyan}x=0 \;is \;the\;zero\;of\;p(x)} \\\\</p><p></p><p>{\color{green}For\:x=-4\;we\; have} \\\\</p><p></p><p>{\color{green}p(-4)=(-4)^2+4(-4)} \\\\</p><p></p><p>{\color{green}p(-4)=(16-16)} \\\\</p><p></p><p>{\color{green}p(-4)=0} \\\\</p><p></p><p>{\color{green}0=0} \\\\</p><p></p><p></p><p>\therefore\;\;{\color{cyan}x=-4\;is \;the\;zero\;of\;p(x)} \\\\</p><p></p><p>{\color{red}Hence,\;\;0\;And\;-4\;are\;the\;zeros\;of\;p(x)}</p><p></p><p>$