Verify that 1, -1, -3 are the zeros of the cubic polynomial x3 + 3x2 – x – 3 and check the relationship
between the zeros and the coefficients.
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Answer:
Step-by-step explanation:
Alpha + beeta+gamma= 1+-1+-3
=-3
=-coefficient of x^2/coefficient of x^3
Alpha. Beeta +beeta.gamma+gamma.alpha=[1×-1]+[-1×-3]+[-3×1]
= -1+3-3
=-1
=coefficient of x/ coefficient of x^3
Alpha. Beeta. Gamma=1×-1×-3
=3
=- constant term/ coefficient of x^3
Hence x3 + 3x2 – x – 3 relationship between the zeros and the coefficients is verified.
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