Question

Verify that 1, -1, -3 are the zeros of the cubic polynomial x3 + 3x2 – x – 3 and check the relationship
between the zeros and the coefficients.

Answer 1

Answer:

Step-by-step explanation:

Alpha + beeta+gamma= 1+-1+-3

=-3

=-coefficient of x^2/coefficient of x^3

Alpha. Beeta +beeta.gamma+gamma.alpha=[1×-1]+[-1×-3]+[-3×1]

= -1+3-3

=-1

=coefficient of x/ coefficient of x^3

Alpha. Beeta. Gamma=1×-1×-3

=3

=- constant term/ coefficient of x^3

Hence x3 + 3x2 – x – 3 relationship between the zeros and the coefficients is verified.

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