verify that 1,-1 and -3 are the zeroes of the cubic polynomial x³+3x²-3 and check the relationship between zeroes and coefficients.
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Step-by-step explanation:
let, x=1
x(1)=x^3 + 3x^2 -3
=1^3 + 3×1^2 - 3
=1+3-3
=1 answer
let, x=(-1)
x(-1)=x^3 + 3x^2 -3
=(-1)^3 + 3 × (-1)^2 -3
=(-1) + 3 -3
=(-1) answer
let, x=(-3)
x(-3)=x^3 + 3x^2 -3
=(-3)^3 + 3×(-3)^2 -3
=(-27) + 3×9 - 3
=(-27) + 27 -3
=(-3) answer
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