verify that 1, 2, 3/2 are the zeros of the cubic polynomial p(x)=2x^3-9x^2+13x-6. then verify the relationship between the zeros and the coefficients of the polynomial.
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The relationship between the zeros and the coefficients of the polynomial is - (-9/2) = - (coefficient of x^2 / coefficient of x^3) and - (-6/2) = - (constant term / coefficient of x^3)
- Given,
- p(x)=2x^3-9x^2+13x-6
- =(2x-3)(x^2-3x+2)
- =(2x-3)(x-1)(x-2)
- when
- p(x)=0
- ⇒(2x-3)(x-1)(x-2) = 0
- ⇒x=1,2,3/2
- now,
- sum of roots,
- =1+2+3/2
- =9/2
- =- (-9/2)
- = - (coefficient of x^2 / coefficient of x^3)
- now,
- product of roots,
- =1*2*3/2
- =6/2
- =-(-6/2)
- = - (constant term / coefficient of x^3)
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Step-by-step explanation:
you can find the explanation in the above picture
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