verify that 1/3 is a zero of the polynomial 6x^3+x^2-10x+3 is 2 also zero of the polynomial.
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Step-by-step explanation:
p(1/3)
=6(1/3)^3 +(1/3)^2 -10/3 +3
=2/9 +1/9 -10/3 +9/3
=1/3 +9/3 -10/3
=0
p(2)
=6(2)^3 +(2)^2 -10(2) +3
=48+4-20+3
=35
So it is not a zero
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