verify that 1,minus 1 .minus 3 are the 0 of the cubic polynomial xcube minus three xsquare minus x minus three
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To verify
minus 1 and minus 3 are the zeros
x^3 - 3x^2 - x
1st x = -1
( -1 )^3 - 3 ( -1 )^2 - ( -1 )
-1 - 3 + 1
- 4 not equal to 0
hence minus 1 is not the zero
2nd x = - 3
( -3 )^3 - 3 ( -3 )^2 - ( -3 )
- 27 - 27 + 3
- 54 + 3
- 51 is not equal to zero
hence minus 3 is not the zero of the given polynomial
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