Verify that -130 is a term of the AP 11, 8, 5, 2, ... . Which term is this?
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Answered by
0
Answer:
an=a+(n-1) d
-130=11+(n-1) 3
-130-11=n-1/3
-141/3=n-1
-47=n-1
-47+1=n
n=-46
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Answered by
0
Answer:
let l be the last term
l = a + ( n - 1 ) d
- 130= 11 + ( n -1 ) * (-3)
-141 =( n-1 ) * (-3)
-141/(-3) = n-1
47=n -1
n =48
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