Math, asked by ajaymehratana01388, 6 months ago

verify that 2, 1, 1 are zeros of the polynomial p(x) = x? - 4x² + 5x – 2. Also verify the
relationship between the zeros and the coefficients.​ jaldi bato aukat se

Answers

Answered by sasmithayamini12
1

Answer:

(i) 2x

3

+x

2

−5x+2;

2

1

,1,−2

p(x)=2x

3

+x

2

−5x+2 .... (1)

Zeroes for this polynomial are

2

1

,1,−2

Substitute the x=

2

1

in equation (1)

p(

2

1

)=2(

2

1

)

3

+(

2

1

)

2

−5(

2

1

)+2

=

4

1

+

4

1

+

2

5

+2

=0

Substitute the x=1 in equation (1)

p(1)=2×1

3

+1

2

−5×1+2

=2+1−5+2=0

Substitute the x=−2 in equation (1)

p(−2)=2(−2)

3

+(−2)

2

−5(−2)+2

=−16+4+10+2=0

Therefore,

2

1

,1,−2 are the zeroes of the given polynomial.

Comparing the given polynomial with ax

3

+bx

2

+cx+d we obtain,

a=2,b=1,c=−5,d=2

Let us assume α=

2

1

, β=1, γ=−2

Sum of the roots = α+β+γ=

2

1

+1=2=

2

−1

=

a

−b

αβ+βγ+αγ=

2

1

+1(−2)+

2

1

(−2)=

2

−5

=

a

c

Product of the roots = αβγ=

2

1

×x×(−2)=

2

−2

=

a

d

Therefore, the relationship between the zeroes and coefficient are verified.

(ii) x

3

−4x

2

+5x−2;2,1,1

p(x)=x

3

−4x

2

+5x−2 .... (1)

Zeroes for this polynomial are 2,1,1

Substitute x=2 in equation (1)

p(2)=2

3

−4×2

2

+5×2−2

=8−16+10−2=0

Substitute x=1 in equation (1)

p(1)=x

3

−4x

2

+5x−2

=1

3

−4(1)

2

+5(1)−2

=1−4+5−2=0

Therefore, 2,1,1 are the zeroes of the given polynomial.

Comparing the given polynomial with ax

3

+bx

2

+cx+d we obtain,

a=1,b=−4,c=5,d=−2

Let us assume α=2, β=1, γ=1

Sum of the roots = α+β+γ=2+1+1=4=−

1

−4

a

−b

Multiplication of two zeroes taking two at a time=αβ+βγ+αγ=(2)(1)+(1)(1)+(2)(1)=5=

1

5

=

a

c

Product of the roots = αβγ=2×1×1=2=−

1

−2

=

a

d

Therefore, the relationship between the zeroes and coefficient are verified.

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