Question

Verify that 2 and -3 are the zeroes of the polynomial q(x) = x2 + x -6

Answer 1

$p(x) = {x}^{2} + x - 6 \\ p(2) = {2}^{2} + 2 - 6 = 4 + 2 - 6 = 0 \\ p( - 3) = ( - 3)^{2} + ( - 3) - 6 = 9 - 3 - 6 = 0$

Since, p(2) and p (-3) are equal to 0

Therefore, 2 and -3 are the zeroes of given polynomial.