verify that 2 and -3 are the zeros of the polynomial. q(x)= x²+x-6
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Answer:
q (x) = x2+x-6
sum of zeroes =2 - 3) = -b/a
= -1 = -1/1
product of zeroes =2×3
=6 = c/a
=6/1 =6/1
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