Verify that 2 is a zero of polynomial x cube + 24 x square - 3 x minus 18
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2^3+24(2)^2-3(2)-18
8+96-6-18
80
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2
Answer:
Given:
- polynomial x³ +24x² -3x -18
To verify:
- That 2 is a root of the given polynomial.
Pre-requisite Knowledge :
zero of a polynomial : if 'a' is the root of the polynomial p(x) then p(a) = 0 .
Solving Question:
we are given the polynomial and are asked to verify whether it the root .For that we can substitute the value 2 in place of 'x' .If it comes to be zero , we can conclude it the root .
Solution:
x³ +24x² -3x -18
substitute ; x = 2
(2)³ +24(2)² - 3(2) -18
⇒ 8 +24*4 -6 -18
⇒ 8 + 96 -6-18
⇒ 104 - 24
⇒ 80
∴ 2 is not the zero of the polynomial.
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