Math, asked by rubyraju5893, 1 year ago

Verify that 2 is a zero of polynomial x cube + 24 x square - 3 x minus 18

Answers

Answered by vsvk84
0

2^3+24(2)^2-3(2)-18

8+96-6-18

80

Answered by KDPatak
2

Answer:

Given:

  •  polynomial  x³ +24x² -3x -18

To verify:

  • That 2 is a root of the given polynomial.

Pre-requisite Knowledge :

zero of a polynomial : if 'a' is the root of the polynomial p(x) then p(a) = 0 .

Solving Question:

we are given the polynomial and are asked to verify whether it the root .For that we can substitute the value 2 in place of 'x' .If it comes to be zero , we can conclude it the root .

Solution:

x³ +24x² -3x -18

substitute ; x = 2

(2)³ +24(2)² - 3(2) -18

8 +24*4 -6 -18

8 + 96 -6-18

104 - 24

80

∴ 2 is not the zero of the polynomial.

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