Question

Verify that -2 is a zero of the polynomial 9x^3+18x^2-x-2

Answer 1

Step-by-step explanation:

Let p(x) = $9x^{3} +18x^{2} -x-2$

It is given that (-2) is a zero of the polynomial p(x).

Substituting the value of x in the equation.

$(9(-2))^{3}+(18(-2))^{2} -(-2)-2\\= -18^{3} -36^{2} +2-2\\= -5832+1296\\= -4536$

∴ -2 is not a zero of the polynomial $9x^{3} +18x^{2} -x-2$

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Answer 2

Step-by-step explanation:

To Verify:-

p(-2)=9x³+18x²-x-2=0

Verification:-

p(-2)=9(-2)³+18(-2)²-(-2)-2=0

9(-8)+(18)(4)+2-2=0

-72+72=0

0=0

LHS=RHS.

∴(-2) is a zero of polynomial 9x³+18x²-x-2.