Question

verify that 2 is a zero of x^3-6x^2+11x-6.​

Answer 1

Answer:

Since (x+1) is a factor of given cubic equation.

∴ it will completely divide the given equation.

Now, (x

3

+6x

2

+11x+6)=(x

2

+5x+6)(x+1)

=(x+2)(x+3)(x+1)

∴ zeros of (x+1)(x+2)(x+3)=0 are

x+1=0⇒x=−1

x+2=0⇒x=−2

x+3=0⇒x=−3

Step-by-step explanation:

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Answer 2

Answer:

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