Verify that -2 is azero of the polynomial 9x*x*x+18x*x-x-2
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Answered by
2
Hey!
If ( -2 ) Will be the Zeros of the given polynomial then it have to give Zero as resultant while putting at the place of x.
p ( x ) = 9x³ + 18x² - x - 2
= 9 × ( -2 )³ + 18 × ( -2 )² - (-2 ) - 2
= 9 × ( -8 ) + 18 × 4 + 2 - 2
= -72 + 72
= 0
Hence , ( -2 ) is the zeros of the polynomial !!
If ( -2 ) Will be the Zeros of the given polynomial then it have to give Zero as resultant while putting at the place of x.
p ( x ) = 9x³ + 18x² - x - 2
= 9 × ( -2 )³ + 18 × ( -2 )² - (-2 ) - 2
= 9 × ( -8 ) + 18 × 4 + 2 - 2
= -72 + 72
= 0
Hence , ( -2 ) is the zeros of the polynomial !!
Answered by
4
Hi,
Here is your answer !
_________________________
Given polynomial,
p(x) = 9x³ + 18x² - x - 2
If -2 is a zero of given polynomial p(x)
Then p(-2) must be equal to 0
Now,
p(-2) = 9(-2)³ + 18(-2)² - (-2) - 2
= 9×(-8) + 18×4 - 2 + 2
= -72 + 72
= 0
Since, p(-2) = 0
Therefore,
It is verified that -2 is a zero of the given polynomial
Here is your answer !
_________________________
Given polynomial,
p(x) = 9x³ + 18x² - x - 2
If -2 is a zero of given polynomial p(x)
Then p(-2) must be equal to 0
Now,
p(-2) = 9(-2)³ + 18(-2)² - (-2) - 2
= 9×(-8) + 18×4 - 2 + 2
= -72 + 72
= 0
Since, p(-2) = 0
Therefore,
It is verified that -2 is a zero of the given polynomial
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