verify that 3, - 1, - 1 / 3 are the zeros of the cubic polynomial P of X equal to 3 x cube minus 5 x square - 11 x minus 3
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Answer:
Step-by-step explanation:
Let f(x)=3x³-5x²-11x-3
x=3
f(3)=81-45-33-3
f(3)=0
x=-1
f(-1)=-3-5+11-3
f(-1)=0
x=-1/3
f(-1/3)=(-1/9)-(5/9)+11/3-3
f(-1/3)=(-6/9)+11/3-3
f(-1/3)=9/3-3
f(-1/3)=3-3=0
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