Question

Verify that 3, - 1 ,- 1 /3 are the zeros of the cubic polynomial p(x)=3x³-5x²-11x-3,​

Answer 1

Answer:

Step-by-step explanation:

P(3)=3(3)^3-5(3)^2-11(3)-3

P(3)=81-45-33-3=0

So 3is zero of polynomial

P(-1)=3(-1)^3-5(-1)^2-11(-1)-3

P(-1)=-3-5+11-3=0

So, - 1 is zero of polynomial

P(-1/3)=3(-1/3)^3-5(-1/3)^2-11(-1/3)-3

P(-1/3)=-3/27-5/9+11/3-3

P(-1/3)=-18/27+2/3

P(-1/3)=-2/3+2/3=0

So - 1/3 is zero of polynomial