Question

Verify that 3, -2, 1 are the zeroes
the cubic polynomial p(x) =
( x³ - 2x²-5x + 6 and verify the
relation between its zeroes and
coefficient​

Answer 1

Answer:

Hloo✌✌

Answer:

Verification: p(x)= x^3-2x^2-5x+6

p(3) = 27-18-15+6=0

p(-2)=-8-8+10+6=0

p(1)=-1-5+6=0

Therefore 3,-2and 1 are the zeroes of the cubic polynomial p(x)=x^3-2x^2-5x+6

Relation between zeroes and coefficients:

alpha + beta + gamma =-b/a

3 + (-2)+1=-(-2)/1

1+1=2

2=2

(alpha beta+ beta gamma+ alpha gamma) =c/a

(3(-2)+(-2)1+3(1))= -5/1

-6 -2 +3= -5

-8+3= -5

-5 = -5

alpha beta gamma = -d/a

3(-2)1 = -6/1

-6 = -6

Hence ,verified.....

Hope it helpsss......✌✌

plzzz mark it as brainliest ✌✌✌✌✌